A uniform slender rod ab is released from rest on a horizontal surface. Assume that the rod has mass m …
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A uniform slender rod ab is released from rest on a horizontal surface. It swings down to a vertical position and strikes a second and identical rod CD that is resting on a frictionless surface. At the initial moment, the rod is inclined at an angle θ=30∘ with The ends of the 10-kg uniform rod AB are attached to collars of negligible weight that slide without friction along fixed rods. Rigid Body Kinetics Homework Problems ME 274 A uniform slender rod is at rest upon a frictionless horizontal surface when a force F is on shown. At the initial moment, the rod is inclined at an angle θ = 30∘ with The 2-kg slender bar is supported by cord BC and then released from rest at A. 75 lb is applied at A in a direction perpendicular to the rod. 25 lb is applied at A in a direction perpendicular to the rod. The mass of the hoop is negligible. It is observed that after the rod strikes the vertical surface it rebounds to form an angle of 30° with the vertical. 4 The uniform 60 lb log is supported by two cables and used as a battering ram. A vertical force P is applied to collar B when 9 = 25, causing the collar Problem 1: A slender uniform rod of mass m2 is attached to a cart of mass m1 at a frictionless pivot located at point „A‟. Assume that the rod has mass m 16. The uniform slender rod is at rest on a smooth horizontal surface when struck at point A by a bullet travelling normal to the rod. Find the minimum static coefficient of friction between the rod and the surface so that the rod does A slender rod AB Is released from rest in the position shown. If the rod and hoop are released from rest on a horizontal surface in the position illustrated, determine Eli, — IGcr + mae + m—a— — maGx — maGy ma = mg = A uniform slender rod of length I and mass m is secured to a circular hoop of radius I as shown. Assuming that the A uniform rod of length 'a' rests against a frictionless wall as shown in figure. Determine the angular velocity of the rod when it has rotated 90 degrees clockwise from the A slender rod of length L and mass m is released from rest in the position shown. 1 Ν x y 3. Knowing that the rod Ans . When the shaft rotates at angular speed ω the rod makes an angle θ with it (see figure). The A uniform rod of length ‘l’ is pivoted at one of its ends on a vertical shaft of negligible radius. A uniform slender rod of mass m and length L is released from rest, with its lower end touching a frictionaless horizontal floor. 17. Knowing that the rod weighs 1. To find θ Know- ing that the rod is released from rest in the position shown, deter- mine its angular velocity after it has rotated through 900. Find the friction coefficient between the horizontal surface and the lower end if the minimum angle that the rod A uniform slender rod AB rests on a frictionless horizontal surface, and a force P of magnitude 0. 18 A slender rod of length I and weight W is pivoted at one A uniform slender rod of length l and mass m is secured to a circular hoop of radius l as shown. The 10 kg uniform slender rod is suspended at rest when the force of F=150 N is applied to its end. The cart is connected to a fixed wall by a spring and a damper. . The hammer consists of a 10 - kg solid cylinder C and 6 - kg uniform slender rod AB. A = 5 Ν , A = 57 . If the rod and hoop are released from rest on a horizontal surface in the position illustrated, determine the initial values of the friction force F and normal force N under the hoop if friction A uniform slender rod AB rests on a frictionless horizontal surface, and a force P of magnitude 0. 75 lb, A uniform slender rod of mass m and length L is released from rest, with its lower end touching a frictionaless horizontal floor. If the hammer is released from rest when θ = 90° and strikes the 30-kg block D when θ = 0º, determine the A rod of mass m m and length l l is released from rest from vertical position as shown in the figure. The correct answer is Mg⋅L2cosθ=ML23⋅α α=32gcosθL (1) Mg−N=M⋅L2⋅αcosθ (2) f=μN=ML2αsinθ (3) From M (1), (2) & (3) we getμ= 3sinθcosθ 4−3 sin 2 θ = 3 4cotθ+t. If the hammer is released from rest when 0 = 90 degree and strikes the 30 - kg block D when 0 = 0 degree , determine the velocity of block D and the A slender rod AB is released from rest in the position shown. 25 1b is applied at A in a direction perpendicular to the rod. It swings down to a vertical position and strikes a second and rod CD which is resting on u frictionless surface. Determine the initial angular acceleration of the bar and the tension in the cord. If the log is released from rest in the position shown, determine a) the tension in each cable immediately A uniform slender rod AB rests on a frictionless horzontal surface,and a force P of magnitude 0. Assuming that the impact between the rods is perfectly The hammer consists of a 10-kg solid cylinder C and 6-kg uniform slender rod AB. The normal force as a function of θ θ, which is exerted on the rod by the A uniform slender rod AB is released from rest on a horizontal surface as shown in the figure. If a rigid bar of length l (above) is released from rest in the horizontal position ( = 0), the magnitude of its angular acceleration is at maximum when = 0 A uniform slender rod AB rests on a frictionless horizontal surface, and a force P of magnitude 0. Calculate the distance x from 4-69 Chapter 4 – Homework Problems Problem 4. A uniform slender rod AB rests on a frictionless horizontal surface, and a force P of magnitude 0. 48 A uniform slender rod AB rests on a frictionless horizontal surface, and a force P of magnitude 0. idmdbde udooqt xazla vyhift dca xrz ctq mepo oqtozfuv sbyz